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2/3m=1/6m-12
We move all terms to the left:
2/3m-(1/6m-12)=0
Domain of the equation: 3m!=0
m!=0/3
m!=0
m∈R
Domain of the equation: 6m-12)!=0We get rid of parentheses
m∈R
2/3m-1/6m+12=0
We calculate fractions
12m/18m^2+(-3m)/18m^2+12=0
We multiply all the terms by the denominator
12m+(-3m)+12*18m^2=0
Wy multiply elements
216m^2+12m+(-3m)=0
We get rid of parentheses
216m^2+12m-3m=0
We add all the numbers together, and all the variables
216m^2+9m=0
a = 216; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·216·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*216}=\frac{-18}{432} =-1/24 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*216}=\frac{0}{432} =0 $
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