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2/3m+2=1/6m
We move all terms to the left:
2/3m+2-(1/6m)=0
Domain of the equation: 3m!=0
m!=0/3
m!=0
m∈R
Domain of the equation: 6m)!=0We add all the numbers together, and all the variables
m!=0/1
m!=0
m∈R
2/3m-(+1/6m)+2=0
We get rid of parentheses
2/3m-1/6m+2=0
We calculate fractions
12m/18m^2+(-3m)/18m^2+2=0
We multiply all the terms by the denominator
12m+(-3m)+2*18m^2=0
Wy multiply elements
36m^2+12m+(-3m)=0
We get rid of parentheses
36m^2+12m-3m=0
We add all the numbers together, and all the variables
36m^2+9m=0
a = 36; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·36·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*36}=\frac{-18}{72} =-1/4 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*36}=\frac{0}{72} =0 $
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