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5x^2=20x+15=0
We move all terms to the left:
5x^2-(20x+15)=0
We get rid of parentheses
5x^2-20x-15=0
a = 5; b = -20; c = -15;
Δ = b2-4ac
Δ = -202-4·5·(-15)
Δ = 700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{700}=\sqrt{100*7}=\sqrt{100}*\sqrt{7}=10\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-10\sqrt{7}}{2*5}=\frac{20-10\sqrt{7}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+10\sqrt{7}}{2*5}=\frac{20+10\sqrt{7}}{10} $
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