2/3k+3=6

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Solution for 2/3k+3=6 equation: 



2/3k+3=6

We move all terms to the left:

2/3k+3-(6)=0



Domain of the equation: 3k!=0

k!=0/3

k!=0

k∈R



We add all the numbers together, and all the variables

2/3k-3=0

We multiply all the terms by the denominator


-3*3k+2=0

Wy multiply elements

-9k+2=0

We move all terms containing k to the left, all other terms to the right

-9k=-2

k=-2/-9

k=2/9

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