9(q+8)-(3q-5)=21+11(-2q-13)

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Solution for 9(q+8)-(3q-5)=21+11(-2q-13) equation: 



9(q+8)-(3q-5)=21+11(-2q-13)

We move all terms to the left:

9(q+8)-(3q-5)-(21+11(-2q-13))=0

We multiply parentheses

9q-(3q-5)-(21+11(-2q-13))+72=0

We get rid of parentheses

9q-3q-(21+11(-2q-13))+5+72=0



We calculate terms in parentheses: -(21+11(-2q-13)), so:

21+11(-2q-13)

determiningTheFunctionDomain
11(-2q-13)+21

We multiply parentheses

-22q-143+21

We add all the numbers together, and all the variables

-22q-122

Back to the equation:

-(-22q-122)



We add all the numbers together, and all the variables

6q-(-22q-122)+77=0

We get rid of parentheses

6q+22q+122+77=0

We add all the numbers together, and all the variables

28q+199=0

We move all terms containing q to the left, all other terms to the right

28q=-199

q=-199/28

q=-7+3/28

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