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2/3h=5
We move all terms to the left:
2/3h-(5)=0
Domain of the equation: 3h!=0We multiply all the terms by the denominator
h!=0/3
h!=0
h∈R
-5*3h+2=0
Wy multiply elements
-15h+2=0
We move all terms containing h to the left, all other terms to the right
-15h=-2
h=-2/-15
h=2/15
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