3a-6(a+1)=2-(3a+8)

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Solution for 3a-6(a+1)=2-(3a+8) equation: 



3a-6(a+1)=2-(3a+8)

We move all terms to the left:

3a-6(a+1)-(2-(3a+8))=0

We multiply parentheses

3a-6a-(2-(3a+8))-6=0



We calculate terms in parentheses: -(2-(3a+8)), so:

2-(3a+8)

determiningTheFunctionDomain
-(3a+8)+2

We get rid of parentheses

-3a-8+2

We add all the numbers together, and all the variables

-3a-6

Back to the equation:

-(-3a-6)



We add all the numbers together, and all the variables

-3a-(-3a-6)-6=0

We get rid of parentheses

-3a+3a+6-6=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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