2/3h+5=-4-1/4h

Solution for 2/3h+5=-4-1/4h equation:

2/3h+5=-4-1/4h

We move all terms to the left:

2/3h+5-(-4-1/4h)=0


Domain of the equation: 3h!=0

h!=0/3

h!=0

h∈R



Domain of the equation: 4h)!=0

h!=0/1

h!=0

h∈R


We add all the numbers together, and all the variables

2/3h-(-1/4h-4)+5=0

We get rid of parentheses

2/3h+1/4h+4+5=0

We calculate fractions


8h/12h^2+3h/12h^2+4+5=0

We add all the numbers together, and all the variables

8h/12h^2+3h/12h^2+9=0

We multiply all the terms by the denominator


8h+3h+9*12h^2=0

We add all the numbers together, and all the variables

11h+9*12h^2=0

Wy multiply elements

108h^2+11h=0

a = 108; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·108·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*108}=\frac{-22}{216}
=-11/108
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*108}=\frac{0}{216}
=0
$