(18-2x)(12-2x)=0

Solution for (18-2x)(12-2x)=0 equation:

(18-2x)(12-2x)=0

We add all the numbers together, and all the variables

(-2x+18)(-2x+12)=0

We multiply parentheses ..

(+4x^2-24x-36x+216)=0

We get rid of parentheses

4x^2-24x-36x+216=0

We add all the numbers together, and all the variables

4x^2-60x+216=0

a = 4; b = -60; c = +216;
Δ = b2-4ac
Δ = -602-4·4·216
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-12}{2*4}=\frac{48}{8}
=6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+12}{2*4}=\frac{72}{8}
=9
$