2/3h+1/4h=22

Solution for 2/3h+1/4h=22 equation:

2/3h+1/4h=22

We move all terms to the left:

2/3h+1/4h-(22)=0


Domain of the equation: 3h!=0

h!=0/3

h!=0

h∈R



Domain of the equation: 4h!=0

h!=0/4

h!=0

h∈R


We calculate fractions


8h/12h^2+3h/12h^2-22=0

We multiply all the terms by the denominator


8h+3h-22*12h^2=0

We add all the numbers together, and all the variables

11h-22*12h^2=0

Wy multiply elements

-264h^2+11h=0

a = -264; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-264)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-264}=\frac{-22}{-528}
=1/24
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-264}=\frac{0}{-528}
=0
$