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2/3e-1=e-6
We move all terms to the left:
2/3e-1-(e-6)=0
Domain of the equation: 3e!=0We get rid of parentheses
e!=0/3
e!=0
e∈R
2/3e-e+6-1=0
We multiply all the terms by the denominator
-e*3e+6*3e-1*3e+2=0
Wy multiply elements
-3e^2+18e-3e+2=0
We add all the numbers together, and all the variables
-3e^2+15e+2=0
a = -3; b = 15; c = +2;
Δ = b2-4ac
Δ = 152-4·(-3)·2
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{249}}{2*-3}=\frac{-15-\sqrt{249}}{-6} $$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{249}}{2*-3}=\frac{-15+\sqrt{249}}{-6} $
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