(4y-5)=11(y-10)

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Solution for (4y-5)=11(y-10) equation: 



(4y-5)=11(y-10)

We move all terms to the left:

(4y-5)-(11(y-10))=0

We get rid of parentheses

4y-(11(y-10))-5=0



We calculate terms in parentheses: -(11(y-10)), so:

11(y-10)

We multiply parentheses

11y-110

Back to the equation:

-(11y-110)



We get rid of parentheses

4y-11y+110-5=0

We add all the numbers together, and all the variables

-7y+105=0

We move all terms containing y to the left, all other terms to the right

-7y=-105

y=-105/-7

y=+15

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