2/3c+10=6

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Solution for 2/3c+10=6 equation: 



2/3c+10=6

We move all terms to the left:

2/3c+10-(6)=0



Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R



We add all the numbers together, and all the variables

2/3c+4=0

We multiply all the terms by the denominator


4*3c+2=0

Wy multiply elements

12c+2=0

We move all terms containing c to the left, all other terms to the right

12c=-2

c=-2/12

c=-1/6

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