8(y-5)=2(10+4y)

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Solution for 8(y-5)=2(10+4y) equation: 



8(y-5)=2(10+4y)

We move all terms to the left:

8(y-5)-(2(10+4y))=0

We add all the numbers together, and all the variables

8(y-5)-(2(4y+10))=0

We multiply parentheses

8y-(2(4y+10))-40=0



We calculate terms in parentheses: -(2(4y+10)), so:

2(4y+10)

We multiply parentheses

8y+20

Back to the equation:

-(8y+20)



We get rid of parentheses

8y-8y-20-40=0

We add all the numbers together, and all the variables

-60!=0

There is no solution for this equation

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