2/3-(n-3)=2/3n+4

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Solution for 2/3-(n-3)=2/3n+4 equation: 



2/3-(n-3)=2/3n+4

We move all terms to the left:

2/3-(n-3)-(2/3n+4)=0



Domain of the equation: 3n+4)!=0

n∈R



We get rid of parentheses

-n-2/3n+3-4+2/3=0

We calculate fractions


-n+3-4=0

We add all the numbers together, and all the variables

-1n-1=0

We move all terms containing n to the left, all other terms to the right

-n=1

n=1/-1

n=-1

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