7(-3y+2)=8(3y-2)=

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Solution for 7(-3y+2)=8(3y-2)= equation: 



7(-3y+2)=8(3y-2)=

We move all terms to the left:

7(-3y+2)-(8(3y-2))=0

We multiply parentheses

-21y-(8(3y-2))+14=0



We calculate terms in parentheses: -(8(3y-2)), so:

8(3y-2)

We multiply parentheses

24y-16

Back to the equation:

-(24y-16)



We get rid of parentheses

-21y-24y+16+14=0

We add all the numbers together, and all the variables

-45y+30=0

We move all terms containing y to the left, all other terms to the right

-45y=-30

y=-30/-45

y=2/3

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