2/3(x-6)=1/6(x+12)

Solution for 2/3(x-6)=1/6(x+12) equation:

2/3(x-6)=1/6(x+12)

We move all terms to the left:

2/3(x-6)-(1/6(x+12))=0


Domain of the equation: 3(x-6)!=0

x∈R



Domain of the equation: 6(x+12))!=0

x∈R


We calculate fractions


(12xx/(3(x-6)*6(x+12)))+(-3xx/(3(x-6)*6(x+12)))=0


We calculate terms in parentheses: +(12xx/(3(x-6)*6(x+12))), so:

12xx/(3(x-6)*6(x+12))

We multiply all the terms by the denominator


12xx

Back to the equation:

+(12xx)



We calculate terms in parentheses: +(-3xx/(3(x-6)*6(x+12))), so:

-3xx/(3(x-6)*6(x+12))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)


We get rid of parentheses

12xx-3xx=0