(10x-11)=(3x-2)(3x+1)

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Solution for (10x-11)=(3x-2)(3x+1) equation: 



(10x-11)=(3x-2)(3x+1)

We move all terms to the left:

(10x-11)-((3x-2)(3x+1))=0

We get rid of parentheses

10x-((3x-2)(3x+1))-11=0

We multiply parentheses ..

-((+9x^2+3x-6x-2))+10x-11=0



We calculate terms in parentheses: -((+9x^2+3x-6x-2)), so:

(+9x^2+3x-6x-2)

We get rid of parentheses

9x^2+3x-6x-2

We add all the numbers together, and all the variables

9x^2-3x-2

Back to the equation:

-(9x^2-3x-2)



We add all the numbers together, and all the variables

10x-(9x^2-3x-2)-11=0

We get rid of parentheses

-9x^2+10x+3x+2-11=0

We add all the numbers together, and all the variables

-9x^2+13x-9=0

a = -9; b = 13; c = -9;
Δ = b2-4ac
Δ = 132-4·(-9)·(-9)
Δ = -155
Delta is less than zero, so there is no solution for the equation

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