2x+40x2+10x=360

Solution for 2x+40x2+10x=360 equation:

2x+40x^2+10x=360

We move all terms to the left:

2x+40x^2+10x-(360)=0

We add all the numbers together, and all the variables

40x^2+12x-360=0

a = 40; b = 12; c = -360;
Δ = b2-4ac
Δ = 122-4·40·(-360)
Δ = 57744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{57744}=\sqrt{144*401}=\sqrt{144}*\sqrt{401}=12\sqrt{401}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12\sqrt{401}}{2*40}=\frac{-12-12\sqrt{401}}{80}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12\sqrt{401}}{2*40}=\frac{-12+12\sqrt{401}}{80}
$