2/3(x-5)=5/6(2x-8)

Solution for 2/3(x-5)=5/6(2x-8) equation:

2/3(x-5)=5/6(2x-8)

We move all terms to the left:

2/3(x-5)-(5/6(2x-8))=0


Domain of the equation: 3(x-5)!=0

x∈R



Domain of the equation: 6(2x-8))!=0

x∈R


We calculate fractions


(12x2/(3(x-5)*6(2x-8)))+(-15xx/(3(x-5)*6(2x-8)))=0


We calculate terms in parentheses: +(12x2/(3(x-5)*6(2x-8))), so:

12x2/(3(x-5)*6(2x-8))

We multiply all the terms by the denominator


12x2

We add all the numbers together, and all the variables

12x^2

Back to the equation:

+(12x^2)



We calculate terms in parentheses: +(-15xx/(3(x-5)*6(2x-8))), so:

-15xx/(3(x-5)*6(2x-8))

We multiply all the terms by the denominator


-15xx

Back to the equation:

+(-15xx)


We get rid of parentheses

12x^2-15xx=0