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12+1/5x+3=10
We move all terms to the left:
12+1/5x+3-(10)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
1/5x+5=0
We multiply all the terms by the denominator
5*5x+1=0
Wy multiply elements
25x+1=0
We move all terms containing x to the left, all other terms to the right
25x=-1
x=-1/25
x=-1/25
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