2/3(x-5)=1/6(3x+1)

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Solution for 2/3(x-5)=1/6(3x+1) equation: 



2/3(x-5)=1/6(3x+1)

We move all terms to the left:

2/3(x-5)-(1/6(3x+1))=0



Domain of the equation: 3(x-5)!=0

x∈R





Domain of the equation: 6(3x+1))!=0

x∈R



We calculate fractions


(12x3/(3(x-5)*6(3x+1)))+(-3xx/(3(x-5)*6(3x+1)))=0



We calculate terms in parentheses: +(12x3/(3(x-5)*6(3x+1))), so:

12x3/(3(x-5)*6(3x+1))

We multiply all the terms by the denominator


12x3

We add all the numbers together, and all the variables

12x^3

We do not support expression: x^3

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