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2/3(x-12)=-1/3x+24
We move all terms to the left:
2/3(x-12)-(-1/3x+24)=0
Domain of the equation: 3(x-12)!=0
x∈R
Domain of the equation: 3x+24)!=0We get rid of parentheses
x∈R
2/3(x-12)+1/3x-24=0
We calculate fractions
6x/(9x^2-108x)+(3xx/(9x^2-108x)-24=0
We calculate fractions
We do not support expression: x^3
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