5(2x)(3x-10)=180

Solution for 5(2x)(3x-10)=180 equation:

5(2x)(3x-10)=180

We move all terms to the left:

5(2x)(3x-10)-(180)=0

We multiply parentheses

156x^2-520x-180=0

a = 156; b = -520; c = -180;
Δ = b2-4ac
Δ = -5202-4·156·(-180)
Δ = 382720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{382720}=\sqrt{256*1495}=\sqrt{256}*\sqrt{1495}=16\sqrt{1495}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-520)-16\sqrt{1495}}{2*156}=\frac{520-16\sqrt{1495}}{312}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-520)+16\sqrt{1495}}{2*156}=\frac{520+16\sqrt{1495}}{312}
$