2/3(x+3)=1/2(x-1)

Solution for 2/3(x+3)=1/2(x-1) equation:

2/3(x+3)=1/2(x-1)

We move all terms to the left:

2/3(x+3)-(1/2(x-1))=0


Domain of the equation: 3(x+3)!=0

x∈R



Domain of the equation: 2(x-1))!=0

x∈R


We calculate fractions


(4xx/(3(x+3)*2(x-1)))+(-3xx/(3(x+3)*2(x-1)))=0


We calculate terms in parentheses: +(4xx/(3(x+3)*2(x-1))), so:

4xx/(3(x+3)*2(x-1))

We multiply all the terms by the denominator


4xx

Back to the equation:

+(4xx)



We calculate terms in parentheses: +(-3xx/(3(x+3)*2(x-1))), so:

-3xx/(3(x+3)*2(x-1))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)


We get rid of parentheses

4xx-3xx=0