2/3(v-3)=1/3(v=6)

Solution for 2/3(v-3)=1/3(v=6) equation:

2/3(v-3)=1/3(v=6)

We move all terms to the left:

2/3(v-3)-(1/3(v)=0


Domain of the equation: 3(v-3)!=0

v∈R



Domain of the equation: 3v!=0

v!=0/3

v!=0

v∈R


We calculate fractions


6v/(9v^2-27v)+(-3vv/(9v^2-27v)=0


We calculate terms in parentheses: +(-3vv/(9v^2-27v), so:

-3vv/(9v^2-27v

We multiply all the terms by the denominator


-3vv

Back to the equation:

+(-3vv)


We get rid of parentheses

6v/(9v^2-27v)-3vv=0

We multiply all the terms by the denominator


6v-3vv*(9v^2-27v)=0

We multiply parentheses

-27v^3+81v^2+6v=0

We do not support evpression: v^3