(3x2-5=)

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Solution for (3x2-5=) equation: 



(3x^2-5=)

We move all terms to the left:

(3x^2-5-())=0



We calculate terms in parentheses: +(3x^2-5-()), so:

3x^2-5-()

We add all the numbers together, and all the variables

3x^2

Back to the equation:

+(3x^2)



a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$

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