2/3(t-6)+1=5

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Solution for 2/3(t-6)+1=5 equation: 



2/3(t-6)+1=5

We move all terms to the left:

2/3(t-6)+1-(5)=0



Domain of the equation: 3(t-6)!=0

t∈R



We add all the numbers together, and all the variables

2/3(t-6)-4=0

We multiply all the terms by the denominator


-4*3(t-6)+2=0

Wy multiply elements

-12t(t+2=0

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