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(2x-4)/5+8/5=3(x-1)
We move all terms to the left:
(2x-4)/5+8/5-(3(x-1))=0
We multiply all the terms by the denominator
(2x-4)-((3(x-1)))*5+8=0
We get rid of parentheses
2x-((3(x-1)))*5-4+8=0
We add all the numbers together, and all the variables
2x-((3(x-1)))*5+4=0
We move all terms containing x to the left, all other terms to the right
2x-((3(x-1)))*5=-4
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