2/3(p-12)=10

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Solution for 2/3(p-12)=10 equation: 



2/3(p-12)=10

We move all terms to the left:

2/3(p-12)-(10)=0



Domain of the equation: 3(p-12)!=0

p∈R



We multiply all the terms by the denominator


-10*3(p-12)+2=0

Wy multiply elements

-30p(p+2=0

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