2c+3(c+1)=48

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Solution for 2c+3(c+1)=48 equation: 



2c+3(c+1)=48

We move all terms to the left:

2c+3(c+1)-(48)=0

We multiply parentheses

2c+3c+3-48=0

We add all the numbers together, and all the variables

5c-45=0

We move all terms containing c to the left, all other terms to the right

5c=45

c=45/5

c=9

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