2/3(p-12)=-(2p-1+7

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Solution for 2/3(p-12)=-(2p-1+7 equation: 



2/3(p-12)=-(2p-1+7

We move all terms to the left:

2/3(p-12)-(-(2p-1+7)=0



Domain of the equation: 3(p-12)!=0

p∈R



We add all the numbers together, and all the variables

2/3(p-12)-(-(2p+6)=0

We multiply all the terms by the denominator


-((-(2p+6))*3(p-12)+2=0

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