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3(3x-2)+4x=9x+6-2x
We move all terms to the left:
3(3x-2)+4x-(9x+6-2x)=0
We add all the numbers together, and all the variables
3(3x-2)+4x-(7x+6)=0
We add all the numbers together, and all the variables
4x+3(3x-2)-(7x+6)=0
We multiply parentheses
4x+9x-(7x+6)-6=0
We get rid of parentheses
4x+9x-7x-6-6=0
We add all the numbers together, and all the variables
6x-12=0
We move all terms containing x to the left, all other terms to the right
6x=12
x=12/6
x=2
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