2/3(c-3)=7

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Solution for 2/3(c-3)=7 equation: 



2/3(c-3)=7

We move all terms to the left:

2/3(c-3)-(7)=0



Domain of the equation: 3(c-3)!=0

c∈R



We multiply all the terms by the denominator


-7*3(c-3)+2=0

Wy multiply elements

-21c(c+2=0

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