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1/313(9k+3)=-2k+16
We move all terms to the left:
1/313(9k+3)-(-2k+16)=0
Domain of the equation: 313(9k+3)!=0We get rid of parentheses
k∈R
1/313(9k+3)+2k-16=0
We multiply all the terms by the denominator
2k*313(9k+3)-16*313(9k+3)+1=0
Wy multiply elements
626k^2(9-5008k(9+1=0
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