2/3(9y-3)=y+4

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Solution for 2/3(9y-3)=y+4 equation: 



2/3(9y-3)=y+4

We move all terms to the left:

2/3(9y-3)-(y+4)=0



Domain of the equation: 3(9y-3)!=0

y∈R



We get rid of parentheses

2/3(9y-3)-y-4=0

We multiply all the terms by the denominator


-y*3(9y-3)-4*3(9y-3)+2=0

Wy multiply elements

-3y^2(9-12y(9+2=0

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