2(x+2)+5(x+5)=(x-8)+2(x-2)

Solution for 2(x+2)+5(x+5)=(x-8)+2(x-2) equation:

2(x+2)+5(x+5)=(x-8)+2(x-2)

We move all terms to the left:

2(x+2)+5(x+5)-((x-8)+2(x-2))=0

We multiply parentheses

2x+5x-((x-8)+2(x-2))+4+25=0


We calculate terms in parentheses: -((x-8)+2(x-2)), so:

(x-8)+2(x-2)

We multiply parentheses

(x-8)+2x-4

We get rid of parentheses

x+2x-8-4

We add all the numbers together, and all the variables

3x-12

Back to the equation:

-(3x-12)


We add all the numbers together, and all the variables

7x-(3x-12)+29=0

We get rid of parentheses

7x-3x+12+29=0

We add all the numbers together, and all the variables

4x+41=0

We move all terms containing x to the left, all other terms to the right

4x=-41

x=-41/4

x=-10+1/4