2/3(9x-6)=x+8

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Solution for 2/3(9x-6)=x+8 equation: 



2/3(9x-6)=x+8

We move all terms to the left:

2/3(9x-6)-(x+8)=0



Domain of the equation: 3(9x-6)!=0

x∈R



We get rid of parentheses

2/3(9x-6)-x-8=0

We multiply all the terms by the denominator


-x*3(9x-6)-8*3(9x-6)+2=0

Wy multiply elements

-3x^2(9-24x(9+2=0

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