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3(-2-1)+2(x-2+1)=-(3x-3+1)
We move all terms to the left:
3(-2-1)+2(x-2+1)-(-(3x-3+1))=0
We add all the numbers together, and all the variables
2(x-1)-(-(3x-2))+3(-3)=0
We add all the numbers together, and all the variables
2(x-1)-(-(3x-2))-9=0
We multiply parentheses
2x-(-(3x-2))-2-9=0
We calculate terms in parentheses: -(-(3x-2)), so:We add all the numbers together, and all the variables
-(3x-2)
We get rid of parentheses
-3x+2
Back to the equation:
-(-3x+2)
2x-(-3x+2)-11=0
We get rid of parentheses
2x+3x-2-11=0
We add all the numbers together, and all the variables
5x-13=0
We move all terms containing x to the left, all other terms to the right
5x=13
x=13/5
x=2+3/5
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