2/3(9x-6)=10x-4x+10

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Solution for 2/3(9x-6)=10x-4x+10 equation: 



2/3(9x-6)=10x-4x+10

We move all terms to the left:

2/3(9x-6)-(10x-4x+10)=0



Domain of the equation: 3(9x-6)!=0

x∈R



We add all the numbers together, and all the variables

2/3(9x-6)-(6x+10)=0

We get rid of parentheses

2/3(9x-6)-6x-10=0

We multiply all the terms by the denominator


-6x*3(9x-6)-10*3(9x-6)+2=0

Wy multiply elements

-18x^2(9-30x(9+2=0

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