40-3(x-5)=5+7x

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Solution for 40-3(x-5)=5+7x equation: 



40-3(x-5)=5+7x

We move all terms to the left:

40-3(x-5)-(5+7x)=0

We add all the numbers together, and all the variables

-3(x-5)-(7x+5)+40=0

We multiply parentheses

-3x-(7x+5)+15+40=0

We get rid of parentheses

-3x-7x-5+15+40=0

We add all the numbers together, and all the variables

-10x+50=0

We move all terms containing x to the left, all other terms to the right

-10x=-50

x=-50/-10

x=+5

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