2/3(9x-3)=5x+4-x

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Solution for 2/3(9x-3)=5x+4-x equation: 



2/3(9x-3)=5x+4-x

We move all terms to the left:

2/3(9x-3)-(5x+4-x)=0



Domain of the equation: 3(9x-3)!=0

x∈R



We add all the numbers together, and all the variables

2/3(9x-3)-(4x+4)=0

We get rid of parentheses

2/3(9x-3)-4x-4=0

We multiply all the terms by the denominator


-4x*3(9x-3)-4*3(9x-3)+2=0

Wy multiply elements

-12x^2(9-12x(9+2=0

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