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2x+3=5-(x+3)+3x
We move all terms to the left:
2x+3-(5-(x+3)+3x)=0
We calculate terms in parentheses: -(5-(x+3)+3x), so:We get rid of parentheses
5-(x+3)+3x
determiningTheFunctionDomain -(x+3)+3x+5
We add all the numbers together, and all the variables
3x-(x+3)+5
We get rid of parentheses
3x-x-3+5
We add all the numbers together, and all the variables
2x+2
Back to the equation:
-(2x+2)
2x-2x-2+3=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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