2/3(9x-12)=6x+7

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Solution for 2/3(9x-12)=6x+7 equation: 



2/3(9x-12)=6x+7

We move all terms to the left:

2/3(9x-12)-(6x+7)=0



Domain of the equation: 3(9x-12)!=0

x∈R



We get rid of parentheses

2/3(9x-12)-6x-7=0

We multiply all the terms by the denominator


-6x*3(9x-12)-7*3(9x-12)+2=0

Wy multiply elements

-18x^2(9-21x(9+2=0

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