2/3(9x+12)-18=-1/5(25x-20)

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Solution for 2/3(9x+12)-18=-1/5(25x-20) equation: 



2/3(9x+12)-18=-1/5(25x-20)

We move all terms to the left:

2/3(9x+12)-18-(-1/5(25x-20))=0



Domain of the equation: 3(9x+12)!=0

x∈R





Domain of the equation: 5(25x-20))!=0

x∈R



We calculate fractions


(10x2/(3(9x+12)*5(25x-20)))+(-(-3x9)/(3(9x+12)*5(25x-20)))-18=0



We calculate terms in parentheses: +(10x2/(3(9x+12)*5(25x-20))), so:

10x2/(3(9x+12)*5(25x-20))

We multiply all the terms by the denominator


10x2

We add all the numbers together, and all the variables

10x^2

Back to the equation:

+(10x^2)





We calculate terms in parentheses: +(-(-3x9)/(3(9x+12)*5(25x-20))), so:

-(-3x9)/(3(9x+12)*5(25x-20))

We add all the numbers together, and all the variables

-(-3x^9)/(3(9x+12)*5(25x-20))

We multiply all the terms by the denominator


-(-3x^9)

We do not support expression: x^9

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