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2/3(9+6y)-2y=2(y+3)
We move all terms to the left:
2/3(9+6y)-2y-(2(y+3))=0
Domain of the equation: 3(9+6y)!=0We add all the numbers together, and all the variables
y∈R
2/3(6y+9)-2y-(2(y+3))=0
We add all the numbers together, and all the variables
-2y+2/3(6y+9)-(2(y+3))=0
We multiply all the terms by the denominator
-2y*3(6y+9)-((2(y+3)))*3(6y+9)+2=0
We calculate terms in parentheses: -((2(y+3)))*3(6y+9), so:Wy multiply elements
(2(y+3)))*3(6y+9
-6y^2(6-((2(y+3)))*3(6y+9)+2=0
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