10+y=1/3(42+y)

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Solution for 10+y=1/3(42+y) equation: 



10+y=1/3(42+y)

We move all terms to the left:

10+y-(1/3(42+y))=0



Domain of the equation: 3(42+y))!=0

y∈R



We add all the numbers together, and all the variables

y-(1/3(y+42))+10=0

We multiply all the terms by the denominator


y*3(y+42))-(1+10*3(y+42))=0

Wy multiply elements

3y^2(y+30y(y=0

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