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2/3(9+3x)=6x
We move all terms to the left:
2/3(9+3x)-(6x)=0
Domain of the equation: 3(9+3x)!=0We add all the numbers together, and all the variables
x∈R
2/3(3x+9)-6x=0
We add all the numbers together, and all the variables
-6x+2/3(3x+9)=0
We multiply all the terms by the denominator
-6x*3(3x+9)+2=0
Wy multiply elements
-18x^2(3+2=0
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