2(10-2c)=8c+8

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Solution for 2(10-2c)=8c+8 equation: 



2(10-2c)=8c+8

We move all terms to the left:

2(10-2c)-(8c+8)=0

We add all the numbers together, and all the variables

2(-2c+10)-(8c+8)=0

We multiply parentheses

-4c-(8c+8)+20=0

We get rid of parentheses

-4c-8c-8+20=0

We add all the numbers together, and all the variables

-12c+12=0

We move all terms containing c to the left, all other terms to the right

-12c=-12

c=-12/-12

c=1

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