2/3(6x-3)+3x=19

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Solution for 2/3(6x-3)+3x=19 equation: 



2/3(6x-3)+3x=19

We move all terms to the left:

2/3(6x-3)+3x-(19)=0



Domain of the equation: 3(6x-3)!=0

x∈R



We add all the numbers together, and all the variables

3x+2/3(6x-3)-19=0

We multiply all the terms by the denominator


3x*3(6x-3)-19*3(6x-3)+2=0

Wy multiply elements

9x^2(6-57x(6+2=0

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